PbSO4 is an ionic compound in which sulphate ion, SO42- is the anion. Since the charge on sulphate ion is -2; the charge on Pb ion is +2 and thus the oxidation state of Pb is +2 in PbSO4..
Keeping this in view, how do you find the oxidation number of PbSO4?
Expert Answer:
- Let the oxidation number of Pb=x.
- Oxidation number of S=+6.
- Oxidation number of O=-2.
- Sum of all oxidation number =0.
- Therefore x+6-8=0.
- Therefore oxidation number of Pb is +2.
One may also ask, what is the oxidation number of Pb in Pb3O4? The oxidation number of Pb in Pb3O4 is : A) + 2/3. B) +4. D) +2.
Similarly, it is asked, what is the charge of PbSO4?
, PbO2 is +4 and -4 (multiply O by 2), but on the product side, PbSO4 is +2 and -2. Is the reason that we don't multiply O on the product side by 4 is that SO4 -2 is an ion and so it stays -2, (I guess 2- because it is an oxidation state we're talking about, not a charge).
What is the oxidation state of O in so42?
+6
Related Question Answers
What is the oxidation number of an element?
Oxidation number, also called Oxidation State, the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.How do you get the oxidation number?
1 Answer - The oxidation number of a free element is always 0.
- The oxidation number of a monatomic ion equals the charge of the ion.
- The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.
- The oxidation number of O in compounds is usually -2, but it is -1 in peroxides.
What is the oxidation number of PbS?
But let's look at the oxidation state of each atom. PbS has Pb in the +2 state and S in the -2 state. PbSO4 has O in the -2 state, Pb in the +2 state, and S in the +6 state. So S goes from -2 to +6.What is the charge of pbo2?
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